va_arg
Syntax:
#include <stdarg.h> type va_arg( va_list argptr, type ); void va_end( va_list argptr ); void va_start( va_list argptr, last_parm ); The va_arg() macros are used to pass a variable number of arguments to a function.
For example: int sum( int num, ... ) { int answer = 0; va_list argptr; va_start( argptr, num ); for( ; num > 0; num-- ) { answer += va_arg( argptr, int ); } va_end( argptr ); return( answer ); } int main( void ) { int answer = sum( 4, 4, 3, 2, 1 ); printf( "The answer is %d\n", answer ); return( 0 ); } This code displays 10, which is 4+3+2+1. Here is another example of variable argument function, which is a simple printing function: void my_printf( char *format, ... ) { va_list argptr; va_start( argptr, format ); while( *format != '\0' ) { // string if( *format == 's' ) { char* s = va_arg( argptr, char * ); printf( "Printing a string: %s\n", s ); } // character else if( *format == 'c' ) { char c = (char) va_arg( argptr, int ); printf( "Printing a character: %c\n", c ); break; } // integer else if( *format == 'd' ) { int d = va_arg( argptr, int ); printf( "Printing an integer: %d\n", d ); } *format++; } va_end( argptr ); } int main( void ) { my_printf( "sdc", "This is a string", 29, 'X' ); return( 0 ); } This code displays the following output when run: Printing a string: This is a string Printing an integer: 29 Printing a character: X |